Let a+b+c+ab+bc+ca+abc = 1000

Then The Possible Value Of a+b+c Is

A) 28

B) 36

C) 39

D) 42

hi prakhar

the expression is (a+1)(b+1)(c+1) - 1 = 1000

(a+1)(b+1)(c+1)=1001 = 7*11*13

from here we can conclude a = 6, b= 10 , c= 12

can be the possible values

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